Dedekind-finiteRings

A ring $R$ is said to be Dedekind-finite if for $a,b\in R$, $ab=1$ implies $ba=1$. Certainly if $R$ is commutative, then $R$ is Dedekind-finite. Other examples include

  • The endormophism ring $\mathrm{End}_k(V)$ is Dedekind-finite where $V$ is a finite dimensional vector space over the field $k$. [Linear algebra]
  • An algebraic algebra over a field $k$ is Dedekind-finite. [Ex. 1.12 (p. 23), L]
  • A domain is Dedekind-finite. [Ex. 1.4 (p. 22), L]
  • A semisimple ring is Dedekind-finite. [Ex. 3.10 (p. 46), L]
  • A semilocal ring is Dedekind-finite. [Proposition 20.8 (p. 298), L] (Note. Any local ring is semilocal.)
  • Let $R$ be a ring such that $R/\mathrm{rad}(R)$ contains no infinite direct sum of nonzero right ideals. Then $R$ is Dedekind finite. [Corollary 21.27 (p. 318), L]
  • Let $R$ be a ring with left stable range 1. Then $M_n(R)$ is Dedekind-finite for all $n\geq 1$. [Theorem 20.13 (p. 301), L]

<b>Example.</b> A non-Dedekind-finite ring [p. 4, L]. Let $V$ be a vector space over a field $k$ with countable infinite basis $\{e_i\mid i=1,2,\dots\}$. Let $R=\mathrm{End}_k(V)$. Let $a,b\in R$ be given by $a(e_1)=0$ and $a(e_i)=e_{i-1}$ for all $i\geq 2$, and $b(e_i)=e_{i+1}$ for all $i$. Then $ab=1$ but $ba\not=1$.

<b>Definition.</b> A ring $R$ is called <i>weakly $n$-finite</i> if $M_n(R)$ is Dedekind-finite. Thus, a ring is weakly $1$-finite if and only if it is Dedekind-finite.

<b>Note 1.</b> Weakly $1$-finite ring may not be weakly $2$-finite. As indicated in [Section 3, C], an example is given in [S]. Cohn also give an example in [C].

<b>Note 2.</b> In the article [HL], many properties of Dedekind-finite regular rings are discussed. The word "finite" in the titile of the article refers to "Dedekind-finite"!

<b>Example.</b> Using $a$ and $b$ in the above example of non-Dedekind-finite ring, W Holubowski constructed an upper triangular matrix whose inverse matrix is lower triangular. So take $c\in R$ such that $c(e_1)=e_1$ and $c(e_i)=0$ for all $i\geq 2$. Let $A=\begin{pmatrix}a&0\\c&b\end{pmatrix}$ and $B=\begin{pmatrix}b&c\\0&a\end{pmatrix}$. Then $AB=BA=I$.

<b>Note 3.</b> If $R$ is a Dedekind-finite ring and $S=M_n(R)$, $n\geq 2$, or $n$ is countably infinite, then the inverse of a lower (upper) triangular matrix in $S$ is lower (upper) triangular. Consequently, the ring $L_n(R)$ ($U_n(R)$) of lower (upper) triangular matrices is Dedekind-finite.

<b>Note 4.</b> In the abstract of a talk by Patricio [P], it is stated that <i>if $R$ is a ring with involution, then all lower triangular invertible matrices have lower triangular inverses if and only if the ring R is Dedekind-finite.</i>

<b>Question.</b> Is the statement in Note 4 true? If so, is involution necessary?

<b>Problem.</b> Study similar problems in nearrings.

<b>References</b>

<b>[C]</b> P. M. Cohn, <i>On $n$-simple rings.</i> Algebra univers. 53 (2005) 301–-305.
<b>[H]</b> W. Holubowski, <i>An inverse matrix of an upper triangular matrix can be lower triangular.</i> Discussiones Mathematicae. General Algebra and Applications 22 (2002), 161--166.
<b>[HL]</b> R. E. Hartwig and J. Luh, <i>On finite regular rings</i>. Pacific J. Math. 69 (1977), 73--95.
<b>[L]</b></b> T. Y. Lam. A first course in noncommutative rings, 2nd Edition. Graduate Texts in Mathematics 131. Springer-Verlag, New York 2001.
<b>[P]</b> P. Patricio, <i>Lower triangular matrices with lower triangular Moore-Penrose inverses</i>. All Ireland Algebra Days 2001, May 16-19, 2001, Queen's University Belfast Belfast, Northern Ireland, UK. (Abstract)
<b>[S]</b> J. C. Shepherdson, <i>Inverses and zero divisors in matrix rings</i>, Proc. London Math. 1 (1951), 71–-85.